Posted by **bobjahng2** on Friday, November 19, 2010 at 4:42pm.

follows first-order kinetics and has an activation energy of 244 kJ mol-1. At 684 K, k = 0.00000508 s-1. What is the half-life (min) for this reaction at 427 °C ? Round your answer to 3 significant figures.

I really dont know what to do

- chemistry -
**DrBob222**, Friday, November 19, 2010 at 5:54pm
You have k at one T (684) and you can calculate k at another T (427) with the Arrhenius equation. Then knowing it is first order, you can use

ln(No/N) = kt.

You can use any convenient number (such as 100) for No, use half that for N (50 if you use 100), plug in k at 427 (that's the T for which you want the 1/2 life), and solve for t. That will be the half-life because you have just 1/2 the number of atoms you started with.

## Answer this Question

## Related Questions

- Chemistry - The given reaction, 2N2O5 4NO2 + O2, follows first-order kinetics ...
- Chemistry - 1. The reaction, CO(CH2COOH)2 CO(CH3)2 + 2CO2, follows first-order ...
- chemistry - The given reaction, cyclopropane propene (isomerization), follows ...
- Chemistry - After 62.0 min, 11.0% of a compound has decomposed. What is the half...
- Chemistry - After 53.0 min, 14.0% of a compound has decomposed. What is the half...
- chemistry - After 56.0 min, 25.0% of a compound has decomposed. What is the half...
- CHEM- KINETICS - Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, ...
- chemistry - If the breakdown half-life of a pesticide applied to a farmer’s ...
- Chemistry - Gallium65, a radioactive isotope of gallium, decays by first order-...
- Chemistry(Please check) - The units of a rate constant for zero, first, and ...