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April 16, 2014

April 16, 2014

Posted by **mike** on Friday, November 19, 2010 at 4:22pm.

I am having a hard time with this question. If anyone knows this I would appreciate it very much thanks.

- probability, not data management -
**MathMate**, Friday, November 19, 2010 at 9:01pmThere are four possible outcomes with two aces of the same colour:

1. A♣+A♠

2. A♠+A♣

3. A♥+A♦

4. A♦+A♥

The total number of events is

2P52

=52!/(52-2)!

So the probability is 4/?

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