Posted by Kyo on .
1. The reaction,
CO(CH2COOH)2 CO(CH3)2 + 2CO2,
follows first-order kinetics and has an activation energy of 96.6 kJ mol-1. At 293 K, k = 0.133 s-1. Find the temperature (in K) at which half-live will be 0.00692 min? Round your answer to 3 significant figures.
Okay so i tried converting the half-life back to k by multiplying it by 60 (convert min to s) and than multiplying it by .693 (1st order half life eq)
and than i plugged it into ln(k1/k2) = Ea/R (t1-t2/t1*t2) and got 299K but the answer is 313...
2. The reaction,
H2 + I2 2HI,
has a rate constant k = 0.00110 L mol-1 s-1 at 683 K and k = 0.00275 L mol-1 s-1 at 700 K. What is the rate constant for the reaction at 443 °C? Round your answer to 3 significant figures.
So for this problem i tried finding Ea by using the first set of k and temperatures...and got 214.246 kj/mol but i don't know what to do next