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March 29, 2017

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Use a linear approximation (or differentials) to estimate the given number.
(32.06)^4/5

  • Calculus - ,

    f= (x+a)^4/5
    df= 4/5(x+a)^-1/5 *da

    df appx= 4/5 (1/2)*.06=.024

    f=appx 16+.024= 16.024

  • Calculus - ,

    [32(1 + 0.1875)]^0.8
    = (32^0.8)*(1 + 0.001875]^0.8
    = 16* (1 + 0.8*0.001875 +...]
    = 16*(1.0015 + ...) = 16.024

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