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Posted by on Thursday, November 18, 2010 at 9:00pm.

The 1.4 kg, 40-cm-diameter disk in the figure below is spinning at 260 rpm. How much friction force must the brake apply to the rim to bring the disk to a halt in 4.5 s?

  • Physics - , Thursday, November 18, 2010 at 9:05pm

    torque=momentinertia*ang acceleration

    look up the momentInertia for a disk
    ang acceleration=(260*2PI)/4.5

    torque= frictionforce*radius

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