Posted by jennifer on Thursday, November 18, 2010 at 8:32pm.
A ball is thrown straight upward and returns to the thrower's hand after 2.20 s in the air. A second ball is thrown at an angle of 31.0° with the horizontal. At what speed must the second ball be thrown so that it reaches the same height as the one thrown vertically?

physics  bobpursley, Thursday, November 18, 2010 at 8:35pm
You need the vertical velocities the same.
time in air for the second ball.
vertical velocity at the top is zero.
Vf=Vsin31g*t
Vf=0, so t=Vsin31/g but this time is 1.1 seconds, so solve for V to make that happen.

physics  Anonymous, Wednesday, October 3, 2012 at 9:30am
26.7081046958
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