the perimeter of a rectangle is twice the sum of its width and it length. the perimeter is 40meters and its lenght is 2 meters more than twice its width.

To find the perimeter of a rectangle, you need to add up all the sides. In this case, you are given that the perimeter is 40 meters.

Let's assign variables to the unknowns. Let's say the width of the rectangle is represented by 'w' and the length is represented by 'l.'

From the given information, we know that the perimeter is twice the sum of its width and length. Therefore, the equation for the perimeter can be written as:

Perimeter = 2 × (width + length)

Substituting the values:
40 = 2 × (w + l)

We also know that the length is 2 meters more than twice the width. So, we can represent the length as:

l = 2w + 2

Now, substitute the value of 'l' in the perimeter equation:

40 = 2 × (w + (2w + 2))

Simplify further:

40 = 2 × (3w + 2)

Now distribute:

40 = 6w + 4

Subtract 4 from both sides:

36 = 6w

Divide both sides by 6:

w = 6

Therefore, the width of the rectangle is 6 meters. To find the length, substitute the value of 'w' into the equation for 'l':

l = 2w + 2
l = 2 × 6 + 2
l = 12 + 2
l = 14

Therefore, the length of the rectangle is 14 meters.

So, the width of the rectangle is 6 meters, and the length is 14 meters.

L = 2W + 2

2L + 2W = 40

Substitute 2W+2 for L in second equation and solve for L. Insert that value into the first equation and solve for W. Check by inserting both values into the second equation.

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