Posted by Anonymous on Wednesday, November 17, 2010 at 11:50pm.
A 3.0% by mass solution of H2O2 contains 3.0 g of H2O2 per 100 g of solution.
(3.0 g H2O2 / 100 g solution) x (1.01 g solution / 1 mL solution) x (1000 mL / L) = 30.3 g H2O2 / L
(30.3 g H2O2 / L) x (1 mole H2O2 / 34.01 g H2O2) = 0.8909 moles H2O2 / L = 0.89 M to 2 sig figs
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