Posted by Lindsay on Wednesday, November 17, 2010 at 9:22pm.
Find the sum of the first 40 terms of the arithmetic sequence. 19, 24, 29, 34

arithmetic  bob, Thursday, November 18, 2010 at 6:44pm
dude why do you put su hard question on here and nobody can do it

arithmetic  Bosnian, Friday, November 19, 2010 at 2:04am
In wikipedia type
"Arithmetic progression"
you wil find everythink about Arithmetic progression
Sn=sum of numbers
Sn=(n/2)*[2a1+(n1)*d]
In this case:
n=40
a1=19
d=5
S40=(40/2)*[2*19+(401)*5]=20*(38+39*5)=20*(38+195)=20*233=4660
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