Posted by **Lindsay** on Wednesday, November 17, 2010 at 9:22pm.

Find the sum of the first 40 terms of the arithmetic sequence. 19, 24, 29, 34

- arithmetic -
**bob**, Thursday, November 18, 2010 at 6:44pm
dude why do you put su hard question on here and nobody can do it

- arithmetic -
**Bosnian**, Friday, November 19, 2010 at 2:04am
In wikipedia type

"Arithmetic progression"

you wil find everythink about Arithmetic progression

Sn=sum of numbers

Sn=(n/2)*[2a1+(n-1)*d]

In this case:

n=40

a1=19

d=5

S40=(40/2)*[2*19+(40-1)*5]=20*(38+39*5)=20*(38+195)=20*233=4660

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