Posted by **Frank** on Wednesday, November 17, 2010 at 8:57pm.

At what two points do the graphs of y=2x^2-5x-12 and y=1/2x^2-3x+4 intersect? explain your reasoning.

- Algebra -
**bobpursley**, Wednesday, November 17, 2010 at 8:59pm
They have the same y, and x.

set them equal

2x^2-5x-12=1/2 x^2-3x+4

combine terms, solve for x (both values), then compute y for each x.

- Algebra -
**Frank**, Wednesday, November 17, 2010 at 9:03pm
when i combine the like terms i don't know what the next step is

- Algebra -
**Reiny**, Wednesday, November 17, 2010 at 9:04pm
set y = y

2x^2 - 5x - 12 = (1/2)x^2 - 3x + 4

I don't like fractions, so multiply each term by 2

4x^2 - 10x - 24 = x^2 - 6x + 8

3x^2 -4x - 32 = 0

(x - 4)(3x + 8) = 0

x = 4 or x = -8/3

if x = 4, y = 32 - 20 - 12 = 0

if x = -8/3

y = 128/9 +40/3 - 12 = 140/9

I could have subbed into the other equation to obtain the same y values, since we set them equal

two points are(4,0) and (-8/3, 140/9)

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