Balance the equation:

K2CrO4 + Na2SO3 + HCl --> KCl + Na2SO4 +CrCl3 + H2O

To balance the given chemical equation, we need to make sure that the number of atoms for each element is the same on both sides of the equation.

Let's start by counting the number of atoms for each element on the left and right sides of the equation:

Left side:
K: 2 (from K2CrO4)
Cr: 1 (from K2CrO4)
O: 4 (from K2CrO4)
Na: 2 (from Na2SO3)
S: 1 (from Na2SO3)
H: 1 (from HCl)
Cl: 1 (from HCl)

Right side:
K: 1 (from KCl)
Cr: 1 (from CrCl3)
O: 4 (from Na2SO4 and H2O)
Na: 2 (from Na2SO4)
S: 1 (from Na2SO4)
H: 2 (from H2O)
Cl: 4 (from KCl and CrCl3)

To balance the equation, we can start by balancing the atoms of each element one by one. Let's start with the potassium (K) atoms:

Left side:
K: 2

Right side:
K: 1

To balance the potassium atoms, we can add a coefficient of 2 in front of KCl on the right-hand side:

K2CrO4 + Na2SO3 + HCl --> 2KCl + Na2SO4 + CrCl3 + H2O

Now let's move on to balance the chromium (Cr) atoms:

Left side:
Cr: 1

Right side:
Cr: 1

The chromium atoms are already balanced.

Next, let's balance the oxygen (O) atoms:

Left side:
O: 4

Right side:
O: 4

The oxygen atoms are already balanced.

Now let's balance the sodium (Na) atoms:

Left side:
Na: 2

Right side:
Na: 2

The sodium atoms are already balanced.

Let's balance the sulfur (S) atoms:

Left side:
S: 1

Right side:
S: 1

The sulfur atoms are already balanced.

Finally, let's balance the hydrogen (H) and chlorine (Cl) atoms:

Left side:
H: 1
Cl: 1

Right side:
H: 2
Cl: 4

To balance the hydrogen atoms, we can add a coefficient of 2 in front of HCl on the left-hand side:

K2CrO4 + Na2SO3 + 2HCl --> 2KCl + Na2SO4 + CrCl3 + H2O

To balance the chlorine atoms, we can add a coefficient of 3 in front of CrCl3 on the right-hand side:

K2CrO4 + Na2SO3 + 2HCl --> 2KCl + Na2SO4 + 3CrCl3 + H2O

Now the equation is balanced with the same number of atoms on both sides.

I'll help get you started.

Cr goes from an oxidation state of +6 on the left to +3 on the right. S goes from an oxidation state of +4 on the left to +6 on the right. Everything else is a spectator ion. Follow the usual instructions for balancing redox equations.