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July 30, 2014

July 30, 2014

Posted by **Rhea** on Wednesday, November 17, 2010 at 7:39pm.

What is the canoe's mass?

- Physics -
**bobpursley**, Wednesday, November 17, 2010 at 7:50pmWell, the cg did not move.

The cg is (1.5+2.6) from shore at the start.

cg*totalmass= 3.3*63+masscanoe*(3.3+1.5)

(1.5+2.6)(63+masscanoe)= 3.3*63+masscanoe(4.8)

masscanoe(4.1-4.8)=3.3*63-4.1**63

solve for mass canoe

- Physics -
**Tavis**, Tuesday, November 23, 2010 at 4:23pmbetter to sum torques about the center of mass.

from standing in the middle of the canoe we know that the CM is at x = 1.5+2.6 = 4.1

when the person is 3.3m from the shore that makes them (4.1m-3.3m)=0.8m from the CM and because we know the canoe is 3m long the CM of the canoe is (3.3+1.5)=4.8m from the shore and consequently (4.8m-4.1m)=0.7m from the CM of the system.

now sum the torques about the CM and set equal to zero with CCW rotation as being positive we get

0=(63kg)*(0.8m)-(Mcanoe)*0.7m

Mcanoe=(0.8/0.7)*63kg

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