Chemistry
posted by Ricardo on .
What is the minimum amount of 1.75 m of HCL necessary to produce 28.5 L of H2 at stp?
EQUATION IS AS FOLLOWS:
Mg+2HCL>>MgCl2+H2

Is that an m or an M? I will assume you made a typo or didn't know any better and you meant M. Also, I assume you meant at STP.
28.5L H2 x (1 mole/22.4 L) = ?? moles H2.
moles HCl = ??moles H2 x (2 moles HCl/1 mole H2) = xx moles HCl.
M HCl = moles/liters HCl.
You know M and moles, solve for liters HCl 
i did this and i still got the wrong answer. i got like 56.1 and the answer was 1.5. that's why i was lost

i did the same thing...the answer was 1.65
which is not what i got from the calculation