how do I calculate what temperature is needed to heat 52 grams of ethane to occupy 1200ml?
This makes little sense to me.
I think charles law is needed were pressure and mole mass is constant, temperature and volume varies. Im stuck putting it all together.
Your problem doesn't list any starting conditions. Perhaps you are to use STP.
moles C2H6 = 52/30.07 = about 1.6 but you need to do it more accurately than that.
1 mole will occupy 22.4 L @ STP so 1.6 moles will occupy about 22.4 x 1.6 = about 38 L.
Now I would use (V1/T1) = (V2/T2)
I would call T1 = 273 K and solve for T2 (in Kelvin).
I worked it out to need 8458.6K
would this seem like resonable value?
thank you for you're help
To calculate the temperature needed to heat a certain amount of substance, you will need to use the ideal gas law equation, which relates the pressure, volume, temperature, and amount of gas. The equation is as follows:
PV = nRT
Where:
- P is the pressure of the gas
- V is the volume of the gas
- n is the number of moles of gas
- R is the ideal gas constant (8.314 J/(mol·K))
- T is the temperature of the gas in Kelvin
Since you want to find the temperature, you will rearrange the equation:
T = (PV) / (nR)
To proceed with the calculation, you will need to know the pressure, volume, and number of moles of ethane. However, the given information only includes the mass of ethane. So, we need to determine the number of moles of ethane first using its molar mass.
The molar mass of ethane (C2H6) is:
2 atoms of carbon (C) with a molar mass of 12.01 g/mol = 24.02 g/mol
6 atoms of hydrogen (H) with a molar mass of 1.008 g/mol = 6.048 g/mol
Thus, the molar mass of ethane (C2H6) is 24.02 g/mol + 6.048 g/mol = 30.068 g/mol.
To find the number of moles, divide the given mass of ethane (52 grams) by its molar mass:
n = mass / molar mass
n = 52 g / 30.068 g/mol
Now, you can substitute the values into the ideal gas equation:
T = (PV) / (nR)
Keep in mind that the units of pressure (P) must be consistent with the units of volume (V).
After determining the values for P, V, n, and R, you can calculate the temperature (T) needed to heat 52 grams of ethane to occupy 1200 ml.