A sample of a gas at 0.73 atm occupies a volume of 245 mL. If the temperature remains constant, what will be the new pressure if the volume increases to 633 mL?

use

P1V1=P2V2

(0.73 ×245)÷633=0.28 atm

To find the new pressure when the volume changes, we can use Boyle's Law, which states that the product of pressure and volume is constant at a constant temperature.

Boyle's Law can be expressed as:

P₁V₁ = P₂V₂

where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.

Given that the initial pressure (P₁) is 0.73 atm and the initial volume (V₁) is 245 mL, and we want to find the final pressure (P₂) when the volume (V₂) increases to 633 mL, we can set up the equation:

0.73 atm * 245 mL = P₂ * 633 mL

Now, we can rearrange the equation to solve for P₂:

P₂ = (0.73 atm * 245 mL) / 633 mL

P₂ = 0.73 atm * (245 mL / 633 mL)

P₂ = 0.73 atm * (0.3865)

P₂ ≈ 0.282 atm

Therefore, the new pressure, when the volume increases to 633 mL, will be approximately 0.282 atm.