Posted by cristy on .
How many mL of a 0.217 M aqueous solution of ammonium fluoride, NH4F, must be taken to obtain 3.63 grams of the salt?

chemestry 
Dr Russ,
Start from calculating the molar mass of NH4F, F.
we need therefore, 3.63/F moles of ammonium fluoride.
The solution contains 0.217 M, or 0.217 moles in 1 litre.
which is 1000/0.217 ml mole^1
hence volume required is
(1000/0.217 ml mole^1)x (3.63/F moles )