Posted by **Adam** on Tuesday, November 16, 2010 at 11:43pm.

Evaluate the integral:

the integral of [5e^(2t)]/[1+4e^(2t)]dt.

I used u sub and let u=e^2t and got 5/2arctan(e^2t)+C. But this answer is incorrect. Please help. Thanks

## Answer this Question

## Related Questions

- Calculus - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I ...
- CALC - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I used u ...
- Calculus 2 - The question is: Evaluate the improper integral for a>0. The ...
- Calculus integral - evaluate the integral: integral from -pi/4 to 0 for the ...
- calculus - 8). Part 1 of 2: In the solid the base is a circle x^2+y^2=16 and the...
- calculus (please with steps and explanations) - consider the function f that is ...
- calc - find integral using table of integrals ) integral sin^4xdx this the ...
- calculus - evaluate integral or state that it is diverges integral -oo, -2 [2/(x...
- Calculus - Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if ...
- Calculus II/III - A. Find the integral of the following function. Integral of (x...