if i throw a ball up into the air it will not end up being 800 meters, in the air if it leaves my hand at 5 meters
That's correct! When you throw a ball up into the air, its height will depend on various factors such as the initial velocity, angle of projection, air resistance, and gravity.
To calculate the maximum height the ball will reach, you can use the equations of motion. One commonly used equation is:
h = (v₀² * sin²(θ)) / (2 * g)
where:
- h is the maximum height
- v₀ is the initial velocity (in this case, 5 meters per second)
- θ is the angle of projection (assuming 90 degrees for directly upwards)
- g is the acceleration due to gravity (approximately 9.8 meters per second squared)
Plugging in the values, we have:
h = (5² * sin²(90)) / (2 * 9.8)
h = (25 * 1) / 19.6
h ≈ 1.28 meters
Therefore, if you throw a ball upwards with an initial velocity of 5 meters per second, it will reach a maximum height of approximately 1.28 meters.