Homework Help: Statistics

Posted by Lisa on Tuesday, November 16, 2010 at 9:37pm.

Assume the body temperature of healthy adults are normally distributed with a mean of 98.2 degrees F and a standard deviation of .62 degrees F. If you have a temperature of 99.0 what is your percentile score?

Statistics - qwerty123, Tuesday, November 16, 2010 at 11:26pm
99 - 98.2 = .8

.8 divided by .6 = 1.29...z-score

z-score of 1.29...on table
=.9015 = 90.15 %

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