Wednesday

April 1, 2015

April 1, 2015

Posted by **Adam** on Tuesday, November 16, 2010 at 8:52pm.

the integral of [5e^(2t)]/[1+4e^(2t)]dt.

I used u sub and let u=e^2t and got 5/2arctan(e^2t)+C. But this answer is incorrect. Please help. Thanks

**Answer this Question**

**Related Questions**

Calculus - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I ...

CALC - Evaluate the integral: the integral of [5e^(2t)]/[1+4e^(2t)]dt. I used u ...

Calculus 2 - The question is: Evaluate the improper integral for a>0. The ...

Calculus integral - evaluate the integral: integral from -pi/4 to 0 for the ...

calculus - 8). Part 1 of 2: In the solid the base is a circle x^2+y^2=16 and the...

calc - find integral using table of integrals ) integral sin^4xdx this the ...

calculus - evaluate integral or state that it is diverges integral -oo, -2 [2/(x...

Calculus - Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if ...

Calculus II/III - A. Find the integral of the following function. Integral of (x...

Calculus - F(x) = cos(x) • the integral from 2 to x² + 1 of e^(u² +5)du Find F'(...