what is 8x+4y=16 in slop intercept form?
4 y = -8 x + 16
y = -2 x + 4
To convert the equation 8x + 4y = 16 into slope-intercept form (y = mx + b), follow these steps:
Step 1: Rearrange the equation to isolate the y-variable:
8x + 4y = 16
4y = -8x + 16
Step 2: Divide both sides of the equation by 4 to isolate y:
4y/4 = (-8x + 16)/4
y = -2x + 4
So, the equation 8x + 4y = 16 in slope-intercept form is y = -2x + 4.
To write the equation 8x + 4y = 16 in slope-intercept form, you need to isolate y on one side of the equation.
Step 1: Move 8x to the right side of the equation by subtracting 8x from both sides:
8x + 4y - 8x = 16 - 8x
4y = -8x + 16
Step 2: Divide both sides of the equation by 4 to isolate y:
4y/4 = (-8x + 16)/4
y = -2x + 4
Therefore, the equation 8x + 4y = 16 in slope-intercept form is y = -2x + 4.