Posted by **kitkat** on Tuesday, November 16, 2010 at 5:42pm.

A man bought two vanilla ice cream cones, three chocolate cones, four strawberry cones and one pistachio cone for his ten children. In how many ways can he distribute the flavors among the children?

- math 12 -
**bobpursley**, Tuesday, November 16, 2010 at 6:13pm
VVCCCSSSSP

Well, the P can go 10 ways

The V can go then 9*8 ways

the C can go then 7*6*5

and the S can go 4*3*2*1

so ways: 10!

check my thinking.

but what if we did the strawberry first?

the S can go 10*9*8*7 ways

the V can go 6*5

the P can go 4 ways

the C can go 3*2*1

again, 10!

Believe me?

- math 12 -
**kitkat**, Tuesday, November 16, 2010 at 6:16pm
Yes I did 10!/3!4!2!

- math 12 -
**Reiny**, Tuesday, November 16, 2010 at 6:22pm
number of ways of n! of which we have a of one kind, b of another kind , c of another kind ...

= n!/(a!b!c!..)

so you would have 10!/(2!3!4!) = 12600

- math 12 -
**kitkat**, Tuesday, November 16, 2010 at 6:43pm
that's what I got:) Thanks

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