Posted by kitkat on Tuesday, November 16, 2010 at 5:42pm.
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Well, the P can go 10 ways
The V can go then 9*8 ways
the C can go then 7*6*5
and the S can go 4*3*2*1
so ways: 10!
check my thinking.
but what if we did the strawberry first?
the S can go 10*9*8*7 ways
the V can go 6*5
the P can go 4 ways
the C can go 3*2*1
again, 10!
Believe me?
Yes I did 10!/3!4!2!
number of ways of n! of which we have a of one kind, b of another kind , c of another kind ...
= n!/(a!b!c!..)
so you would have 10!/(2!3!4!) = 12600
that's what I got:) Thanks
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