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January 30, 2015

January 30, 2015

Posted by **kitkat** on Tuesday, November 16, 2010 at 5:42pm.

- math 12 -
**bobpursley**, Tuesday, November 16, 2010 at 6:13pmVVCCCSSSSP

Well, the P can go 10 ways

The V can go then 9*8 ways

the C can go then 7*6*5

and the S can go 4*3*2*1

so ways: 10!

check my thinking.

but what if we did the strawberry first?

the S can go 10*9*8*7 ways

the V can go 6*5

the P can go 4 ways

the C can go 3*2*1

again, 10!

Believe me?

- math 12 -
**kitkat**, Tuesday, November 16, 2010 at 6:16pmYes I did 10!/3!4!2!

- math 12 -
**Reiny**, Tuesday, November 16, 2010 at 6:22pmnumber of ways of n! of which we have a of one kind, b of another kind , c of another kind ...

= n!/(a!b!c!..)

so you would have 10!/(2!3!4!) = 12600

- math 12 -
**kitkat**, Tuesday, November 16, 2010 at 6:43pmthat's what I got:) Thanks

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