student did the Synthesis of Salicylic Acid experiment using 3.93 g of methyl salicylate. This was the limiting reagent for his experiment. What is the theoretical yield of salicylic acid for his experiment?

The theoretical yield is:

You should have included this with your first post. The theoretical yield is the amount of SA produced with the limiting reagent.

To calculate the theoretical yield of salicylic acid, we first need to determine the balanced equation for the synthesis of salicylic acid from methyl salicylate. The balanced equation is as follows:

Methyl salicylate + NaOH → Salicylic acid + Sodium salicylate + Water

From the balanced equation, we can see that the molar ratio between methyl salicylate and salicylic acid is 1:1. This means that for every 1 mole of methyl salicylate, we will obtain 1 mole of salicylic acid.

To calculate the theoretical yield, we need to convert the given mass of methyl salicylate (3.93 g) into moles. We can do this by dividing the mass of methyl salicylate by its molar mass, which is 152.15 g/mol.

Moles of methyl salicylate = 3.93 g / 152.15 g/mol ≈ 0.0258 mol

Since the molar ratio between methyl salicylate and salicylic acid is 1:1, the moles of salicylic acid obtained will be the same as the moles of methyl salicylate.

Therefore, the theoretical yield of salicylic acid for this experiment is approximately 0.0258 mol.