Homework Help: physics

Posted by bobjahng2 on Tuesday, November 16, 2010 at 12:29pm.

In the latest Indian Jones film, Indy is supposed to throw a grenade from his car, which is going 79.0 km/h, to his enemy's car, which is going 102 km/h. The enemy's car is 14.3 m in front of the Indy's when he lets go of the grenade.

If Indy throws the grenade so its initial velocity relative to him is at an angle of 45 degrees above the horizontal, what should the magnitude of the initial velocity be? The cars are both traveling in the same direction on a level road. You can ignore air resistance.

What is the magnitude of velocity compared to earth?

physics - bobpursley, Tuesday, November 16, 2010 at 12:44pm
horizontal distance=(V*cos45-Ic)*time where V is velocity adn Ic is Indy's car speed in m/s
distance= 14+(Ic-Ec)*time
set the distances equal
1) 14+(Ic-Ec)t=(Vcos45-Ic)t
hf=hi+VsinTheta*t-1/2 g t^2
0=Vsin45t-4.9 t^2

t= Vsin45/4.9
put that t into 1), and solve for V. This may be challenging algebra.
physics - bobjahng2, Tuesday, November 16, 2010 at 1:08pm
uhhhh so i understand everything you did, but i am having issues with the algebra. Any tips/hints?

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