A snail begins climbing from the bottom of a well that is 10 feet deep. Each day it climbs 3 feet, and each night it slips down 2 feet. How many days does it take the snail to reach the top of the well?
In each 24-hour period the snail goes up one foot.
The snail will reach the top of the well in 10 days.
Right.
Thank you Ms.Sue
You're welcome, Jansi.
To determine how many days it will take for the snail to reach the top of the well, we need to calculate the number of days it will take for the snail to cover a total distance of 10 feet.
Each day, the snail climbs 3 feet, and each night it slips down 2 feet. So, in a 24-hour cycle (day and night), the snail effectively climbs 1 foot (3 feet climbed - 2 feet slipped).
To reach the top of the well, the snail needs to climb 10 feet. Since it covers 1 foot every 24 hours, we can divide 10 by 1 to find the total number of cycles needed.
10 / 1 = 10 cycles
Therefore, it will take the snail a total of 10 cycles to reach the top of the well. Since each cycle consists of a day and a night, we can divide 10 by 2 to find the number of days.
10 cycles / 2 = 5 days
So, it will take the snail approximately 5 days to reach the top of the well.