Okay, so I got question 1 but I don't know how to solve question 2. Since they are tied in, I'll post both of them.
1. When 0.43g of NaNO2 is allowed to react with an excess of HSO3NH2, the volume of N2 gas produced is 0.145 L. After the reaction is completed, the temperature of water is 24.6 (degrees Celsius) and that of gas is 24.21 (degrees Celsius). The atmospheric pressure is 100.72 kPa. Calculate the molar volume of N2 at 298.15K and 100kPa. You may not use PV=nRT
So for this part of the question, I used P1V1=P2V2.
V2 = 0.146L
That part is okay, but then...
2) When 0.5963g of a sample containing NaNO2 and some inert material is allowed to react with excess HSO3NH2, the volume of N2 gas produced is measured. The volume of N2 gas corrected to 298.15K and 100kPa is calculated to be 0.146L. Find the mass percent of NaNO2 in the sample using the molar volume of N2 at 298.15K and 100kPa (from the previous question).
Please help. :(
To solve question 2, we first need to calculate the number of moles of N2 gas produced using the given volume and molar volume.
First, let's calculate the number of moles of N2 gas produced using the molar volume formula:
n = V / V_m
where n is the number of moles, V is the volume of N2 gas, and V_m is the molar volume at the given conditions.
Given:
V = 0.146 L
V_m = molar volume at 298.15K and 100 kPa (from previous question)
Next, we can use the molar mass of N2 to convert the moles of N2 gas to grams of N2.
Molar mass of N2 = 28.0134 g/mol
Mass of N2 = n * molar mass of N2
Now, let's calculate the number of moles of NaNO2.
Given:
Mass of sample = 0.5963 g
Mass of NaNO2 = mass % of NaNO2 in sample * mass of sample
Finally, we can calculate the mass percent of NaNO2 in the sample.
Mass percent of NaNO2 = (mass of NaNO2 / mass of sample) * 100%
I hope this helps! Let me know if you have any further questions.
To solve question 2, you can use the information given in the question along with the molar volume of N2 calculated from question 1 to find the mass percent of NaNO2 in the sample.
Here's how you can approach it:
Step 1: Calculate the moles of N2 gas produced using the molar volume calculated in question 1.
To calculate the moles of N2 gas, you can use the ideal gas law equation:
PV = nRT
Rearrange the equation to solve for moles (n):
n = PV/RT
Given:
P = 100 kPa
V = 0.146 L
T = 298.15 K
Note: Make sure to convert the given pressure to units of atmosphere (atm) and the given volume to units of liters (L) if necessary, as the ideal gas constant R has units of L·atm/(mol·K).
Substitute the values into the equation and calculate the moles of N2 gas.
Step 2: Calculate the moles of NaNO2.
To find the moles of NaNO2, you can use the molar mass of NaNO2. The molar mass of NaNO2 can be calculated by adding the atomic masses of sodium (Na), nitrogen (N), and two oxygen (O) atoms.
The atomic masses are:
Na = 22.99 g/mol
N = 14.01 g/mol
O = 16.00 g/mol
Calculate the molar mass of NaNO2 and convert the given mass of the sample to moles of NaNO2.
Step 3: Calculate the mass percent of NaNO2 in the sample.
The mass percent of NaNO2 in the sample can be calculated using the formula:
Mass percent = (mass of NaNO2 / total mass of sample) * 100
Substitute the values into the formula and calculate the mass percent of NaNO2 in the sample.
By following these steps, you should be able to find the mass percent of NaNO2 in the given sample. If you encounter any difficulties while performing these calculations, please feel free to ask for further assistance.