Posted by lori on Monday, November 15, 2010 at 8:58pm.
it says there should be 5 roots.
f(1) = 1-1+1-1+1-1 = 0
so (x-1) is a factor
by synthetic division I had
(x-1)(x^4 + x^2 + 1)
x^2 = (-1 ± √-3)/2 = (-1 ± i√3)/2
now take √ of that again.
So we get one real root of x=1 and 4 imaginary roots.
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