Posted by **Bella** on Monday, November 15, 2010 at 2:37pm.

A square, 0.52 m on a side, is mounted so that it can rotate about an axis that passes through the center of the square. This axis is perpendicular to the plane of the square. A force of 15.0 N lies in this plane and is applied to the square. What is the magnitude of the maximum torque (in N*m) such that a force could produce?

- Physics -
**bobpursley**, Monday, November 15, 2010 at 2:56pm
As in a square nut? What would it screw into, a square bolt. Ok Max torque occurs when the force is applied on the corner, the rotational radius would be 1/2 the diagonal of the square (figure that out).

max torque=15*radius N-m

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