Posted by **Bella** on Monday, November 15, 2010 at 2:37pm.

A square, 0.52 m on a side, is mounted so that it can rotate about an axis that passes through the center of the square. This axis is perpendicular to the plane of the square. A force of 15.0 N lies in this plane and is applied to the square. What is the magnitude of the maximum torque (in N*m) such that a force could produce?

- Physics -
**bobpursley**, Monday, November 15, 2010 at 2:56pm
As in a square nut? What would it screw into, a square bolt. Ok Max torque occurs when the force is applied on the corner, the rotational radius would be 1/2 the diagonal of the square (figure that out).

max torque=15*radius N-m

## Answer This Question

## Related Questions

- physics - A square, 0.52 m on a side, is mounted so that it can rotate about an ...
- Physics - A square, 0.69 m on a side, is mounted so that it can rotate about an ...
- Physics - A square, 0.36 m on a side, is mounted so that it can rotate about an ...
- Physics HELP!! - A square, 0.74m on a side, is mounted so that it can rotate ...
- physics - Hi, can someone please help with this question. A thin, uniform rod is...
- Physics - A nonuniform 2.0-kg rod is 2.0 m long. The rod is mounted to rotate ...
- Inertia - A thin, uniform rod is bent into a square of side length a. If the ...
- physics - Four point masses, each of mass 2.0 $kg$ are placed at the corners of ...
- physics - A wheel of diameter 28.0 cm is constrained to rotate in the xy plane, ...
- Inertia - A thin, uniform rod is bent into a square of side length a. If the ...

More Related Questions