How many grams equal 1.0 mol of Azurite, Cu3(CO3)2(OH)2?
moles = grams/molar mass
Substitute and solve for grams.
To determine how many grams equal 1.0 mol of the compound Azurite (Cu3(CO3)2(OH)2), you need to calculate its molar mass. The molar mass is the sum of the atomic masses of all the elements present in the compound.
Let's break down the compound and calculate its molar mass:
Cu3(CO3)2(OH)2
The molar mass of copper (Cu) is 63.55 g/mol. The molar mass of carbon (C) is 12.01 g/mol, oxygen (O) is 16.00 g/mol, and hydrogen (H) is 1.01 g/mol.
Calculating the molar mass:
(3 atoms of Cu) x (63.55 g/mol) = 190.65 g/mol
(2 atoms of C) x (12.01 g/mol) = 24.02 g/mol
(12 atoms of O) x (16.00 g/mol) = 192.00 g/mol
(4 atoms of H) x (1.01 g/mol) = 4.04 g/mol
Now, add up all the individual masses:
190.65 g/mol (Cu) + 24.02 g/mol (C) + 192.00 g/mol (O) + 4.04 g/mol (H) = 410.71 g/mol
So, the molar mass of Azurite (Cu3(CO3)2(OH)2) is 410.71 g/mol. Therefore, 1.0 mol of Azurite is equal to 410.71 grams.