Posted by paul on Monday, November 15, 2010 at 12:25am.
The water acquires a vertical velocity component during the fall equal to
Vy = sqrt(2gH) = 25.5 m/s. Its velocity at the bottom is 25.8 m/s, so the horizontal component at the bottom must be sqrt[(25.8)^2 - (25.5)^2] = 3.9 m/s
That must be the horizontal component at the top also, since it does not change during the fall. It is the velocity magnitude there.
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