Homework Help: Physics

Posted by Al on Sunday, November 14, 2010 at 11:31pm.

A diver running 1.2 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 3.1 s later. How high was the cliff and how far from its base did the diver hit the water?

Physics - George, Monday, September 12, 2011 at 12:54am
vertical drop
S = ut+(1/2)gt²
= 0 + (1/2)(9.8)*(3.1)^2
=47.089s

How far from base
1.2m/s * 3.1s = 3.72m
Physics - Jil, Tuesday, September 18, 2012 at 11:26pm
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