when an aqueous solution BaCl2 is mixied with an aqueois solution of Na2CO3, solid barium carbonate precipitates out of solution. write molecular equation, complete ionic equattionand net equation.
is this the right formula??
BaCl2(aq)+Na2CO3(s)=BaCO3(s)????
The Na2CO3 is Na2CO3(aq). The other product is 2NaCl.
omg...I was wondering where u...I'm studying for a test for weds and I'm so lost with most of this...thank u for your help...
The correct formula for the equation you provided is:
BaCl2(aq) + Na2CO3(aq) → BaCO3(s) + 2NaCl(aq)
Let's break down the equation into its different forms.
Molecular Equation:
This equation represents the reaction without separating the aqueous compounds into their individual ions. It shows the overall chemical equation, including the reactants and products. The molecular equation for the given reaction is:
BaCl2(aq) + Na2CO3(aq) → BaCO3(s) + 2NaCl(aq)
Complete Ionic Equation:
The complete ionic equation shows all the ions present in the reaction, including the spectator ions, which are the ions that appear on both sides of the equation but do not participate in the reaction. In this case, the spectator ions are Na+ and Cl-. The complete ionic equation is:
Ba2+(aq) + 2Cl-(aq) + 2Na+(aq) + CO32-(aq) → BaCO3(s) + 2Na+(aq) + 2Cl-(aq)
Net Ionic Equation:
The net ionic equation includes only the ions that directly participate in the reaction. In this case, the spectator ions, Na+ and Cl-, are removed from the equation. Therefore, the net ionic equation is:
Ba2+(aq) + CO32-(aq) → BaCO3(s)
This net ionic equation represents the core reaction, showing the formation of the solid barium carbonate precipitate.