Physics - momentum
posted by J Velji on .
Two hockey players are traveling at velocities of v1 = 15 m/s and v2 = -16 m/s when they undergo a head-on collision. After the collision, they grab each other and slide away together with a velocity of -3.8 m/s. Hockey player 1 has a mass of 121 kg. What is the mass of the other player?
keep getting the wrong answer..
Show us your work and someone will tell you where you went wrong.
This is a conservation of momentum problem.
P= mv1i + mv2i = (m1 + m2)vf
= 121kg(15m/s) +m2(-16) = (121+m2)(-3.8)
and I keep going wrong from here..
nvm, got it!