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November 1, 2014

November 1, 2014

Posted by **Ashley** on Sunday, November 14, 2010 at 9:23pm.

y = 1640 - 16t^2

y'= -32t

When does the ball hit the ground, and how fast is it going at that time? Give your answer in feet per second and in miles per hour (1 ft/sec = 15/22 mph).

v(t) = mph

v(t) = ft per second

- calculus -
**Reiny**, Sunday, November 14, 2010 at 10:57pmfor the first part solve

0 = 1640 - 16t^2

16t^2 = 1640

t^2 = 102.5

t = 10.124 seconds

sub that into y' to get the velocity in ft/sec

Use the formula given to you to change to mph

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