Posted by **Ashley** on Sunday, November 14, 2010 at 9:23pm.

A ball is dropped from the top of a building. The height, , of the ball above the ground (in feet) is given as a function of time, , (in seconds) by

y = 1640 - 16t^2

y'= -32t

When does the ball hit the ground, and how fast is it going at that time? Give your answer in feet per second and in miles per hour (1 ft/sec = 15/22 mph).

v(t) = mph

v(t) = ft per second

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