Posted by **Ashley** on Sunday, November 14, 2010 at 9:23pm.

A ball is dropped from the top of a building. The height, , of the ball above the ground (in feet) is given as a function of time, , (in seconds) by

y = 1640 - 16t^2

y'= -32t

When does the ball hit the ground, and how fast is it going at that time? Give your answer in feet per second and in miles per hour (1 ft/sec = 15/22 mph).

v(t) = mph

v(t) = ft per second

## Answer This Question

## Related Questions

- Calculus - A ball is dropped from the top of a building. The height, , of the ...
- Algebra - A ball is dropped from the top of a building that is 784 feet high. ...
- calculus - A light is attached to the wall of a building 64 feet above the ...
- Calculus - The height in feet above the ground of a ball thrown upwards from the...
- algebra - a ball is dropped from the top of a building that is known to be 256 ...
- Math - If you are standing near the edge of the top of a 200 feet building and ...
- math - Problem: A ball is dropped from the top of a building that is 250 feet ...
- calculus - A ball is dropped from the same height, but 20 feet away from the ...
- Calculus - Suppose a ball is thrown straight up into the air, and the height of...
- Math - If you are standing near the edge of the top of a 200 feet building and ...

More Related Questions