Can you please tell me if these are right?
Classify the solutes in the following equations as a weak electrolyte, a strong electrolyte of a non electrolyte in water.
a. XY2(s)=X2+(aq) +2Y-(aq)
b. HX(g) ß=H+(aq) + X-(aq)
c. XYZ(s)=XYZ(aq)
d. YOH(s)=Y+(aq) + OH-(aq)
a. strong electrolyte
b. weak electrolyte
c. non electrolyte
d. strong electrolyte
Thank you!
a,c, and d look ok. I don't know about b, partly because I don't know what that strange looking symbol is (looks like a beta) and partly because I don't think it has an answer (the jury is still out until I know what that "beta" marks means).
a. XY2(s)=X2+(aq) +2Y-(aq) - This is a strong electrolyte because it dissociates into ions in water.
b. HX(g) ß=H+(aq) + X-(aq) - This is a weak electrolyte because it only partially dissociates into ions in water.
c. XYZ(s)=XYZ(aq) - This is a non-electrolyte because it does not dissociate into ions in water.
d. YOH(s)=Y+(aq) + OH-(aq) - This is a strong electrolyte because it completely dissociates into ions in water.
So, your answers are correct! Keep up the good work!
Your classifications are correct:
a. XY2(s) = X2+(aq) + 2Y-(aq) - This is a strong electrolyte because it completely dissociates into ions in water.
b. HX(g) ⇌ H+(aq) + X-(aq) - This is a weak electrolyte because it only partially dissociates into ions in water.
c. XYZ(s) = XYZ(aq) - This is a non-electrolyte because it does not dissociate into ions when dissolved in water.
d. YOH(s) = Y+(aq) + OH-(aq) - This is a strong electrolyte because it completely dissociates into ions in water.
Well done!
To classify the solutes in the equations as a weak electrolyte, a strong electrolyte, or a non-electrolyte in water, you need to consider whether the solute dissociates (breaks apart) into ions when dissolved in water. Here's how you can determine the classification for each equation:
a. XY2(s) = X2+(aq) + 2Y-(aq)
In this equation, XY2 dissociates into X2+ and 2Y- ions when dissolved in water. Since it completely dissociates into ions, it is considered a strong electrolyte.
b. HX(g) ↔ H+(aq) + X-(aq)
In this equation, HX(g) dissociates partially into H+ and X- ions when dissolved in water. The presence of the reversible arrow indicates that the dissociation is incomplete. Therefore, it is considered a weak electrolyte.
c. XYZ(s) = XYZ(aq)
In this equation, XYZ does not dissociate into ions when dissolved in water. Therefore, it is considered a non-electrolyte.
d. YOH(s) = Y+(aq) + OH-(aq)
In this equation, YOH dissociates into Y+ and OH- ions when dissolved in water. Similar to equation (a), it completely dissociates into ions and is considered a strong electrolyte.
So to recap, the classification for each equation is as follows:
a. XY2(s) = X2+(aq) + 2Y-(aq) -> strong electrolyte
b. HX(g) ↔ H+(aq) + X-(aq) -> weak electrolyte
c. XYZ(s) = XYZ(aq) -> non-electrolyte
d. YOH(s) = Y+(aq) + OH-(aq) -> strong electrolyte