Calculus Tangent lines
posted by kevin on .
find the equation of a tangent line of
x^(1/4) + y^(1/4) = 4 at the point (16,16)

Use implicit differentiation to find y'.
x^(1/4)+y^(1/4)=4
differentiate with respect to x:
x^(3/4)+y^(3/4)*dy/dx=0
dy/dx
= x^(3/4)*y(3/4)
= x^(3/4)*(4x^(1/4))^3
For x=16,
dy/dx = 1
Find the line that passes through (16,16) with a slope of dy/dx = 1.