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March 30, 2017

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What length pendulum will produce a period of 1.0s?

  • physics - ,

    t = 2p1*sqrt(l/g),
    t^2 = 4 * (pi)^2 * l/g.

    t in seconds.

    l in meters or cm.

    g = acceleration due to gravity:
    9.8 m/s^2 or 980 cm/s^2.

    NOTE: l and g should both be in m/s^2
    or cm/s^2.

    t^2 = 4 * 9.87 * l/9.8 = 1^2,
    39.48l / 9.8 = 1,
    4.03l = 1,
    l = 1 / 4.03 = 0.248 m = 24.8 cm.

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