What approximate change in decibles does an observer experience form a sound source if the oberver moves to a new location that is 67% as far from the source?
23
-23
40
2.76
-2.76
1.94
-1.94
2.57
-2.57
0
do I multiply .67 times 10 log .67?
There will be (1/0.67)^2 = 2.23 times more sound intensity (power) per area at the closer distance
10 x log(10)2.23 = 3.5 dB more
I do not agree with any of the choices.
those are the answer choices in my book...
To find the approximate change in decibels experienced by an observer when they move to a new location that is a certain percentage closer or farther from a sound source, we can use the inverse square law for sound intensity.
The inverse square law states that the intensity of sound decreases inversely proportional to the square of the distance from the source. Mathematically, this can be expressed as:
I2 = I1 * (d1/d2)^2
where I1 is the initial sound intensity, I2 is the final sound intensity, d1 is the initial distance from the source, and d2 is the final distance from the source.
In this case, the observer moves to a new location that is 67% as far from the source, which means the final distance (d2) is 67% of the initial distance (d1). Therefore, d2/d1 = 0.67.
Now, let's take a look at the given answer options:
23 is not a valid answer as it is not related to the explanation.
-23 is not a valid answer as it is not related to the explanation.
40 is not a valid answer as it is not related to the explanation.
2.76 is not a valid answer as it is not related to the explanation.
-2.76 is not a valid answer as it is not related to the explanation.
1.94 is not a valid answer as it is not related to the explanation.
-1.94 is not a valid answer as it is not related to the explanation.
2.57 is not a valid answer as it is not related to the explanation.
-2.57 is not a valid answer as it is not related to the explanation.
0 is not a valid answer as it is not related to the explanation.
None of the given answer options are related to the explanation, so it seems there might be a mistake in the options provided. However, based on the given information, we cannot provide a specific answer without knowing the initial sound intensity or decibel level.