Posted by Jaylee on Sunday, November 14, 2010 at 1:08pm.
Three masses are arranged in an (x, y)
plane.
7 kg (3,1)
8 kg (0,0)
9 kg (1,2)
a) What is the magnitude of the resulting force on the 8 kg mass at the origin? The universal gravitational constant is 6.6726 × 10^−11 N · m^2/kg^2. Answer in units of N.
b) What is the angle of the resultant force on the 9 kg mass at the origin?

PHYSICS CIRCULAR MOTION GRAVITATIONAL CONSTANT  Jaylee, Sunday, November 14, 2010 at 1:09pm
For b): I meant the resultant force on the 8 kg mass at the origin. Sorry!

PHYSICS CIRCULAR MOTION GRAVITATIONAL CONSTANT  bobpursley, Sunday, November 14, 2010 at 2:12pm
calculate the two forces, magnitude and angle, add them. Compare it to this:
fx=G7*8/9 (x) + G9*8/1 x add them to get net force in x direction.
fy=G7*8/1(+y) + G9*8/4 (+y) add them to get net force in y direction
Now add these as vectors.

PHYSICS CIRCULAR MOTION GRAVITATIONAL CONSTANT  Jaylee, Sunday, November 14, 2010 at 2:57pm
I'm sorry, but I'm not understanding your explanation. I figured out the two forces and found the resultant but my answer is wrong and I'm not sure how to use your method.

PHYSICS CIRCULAR MOTION GRAVITATIONAL CONSTANT  KA, Monday, November 28, 2011 at 8:13pm
What does the G stand for? The gravitational constant??
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