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October 25, 2014

October 25, 2014

Posted by **Anonymous** on Sunday, November 14, 2010 at 9:32am.

- 9th grade physics needs help -
**PsyDAG**, Sunday, November 14, 2010 at 9:38amIndicate your subject in the "School Subject" box, so those with expertise in the area will respond to the question

- 9th grade -
**Damon**, Sunday, November 14, 2010 at 10:07amWhat is its initial vertical speed Vo ?

v = Vo - 9.8 t

v = 0 at top

so

t = Vo/9.8

then height

h = Vo t - (9.8/2) t^2

100 = Vo^2/9.8 - (9.8/2) (Vo/9.8)^2

100 = Vo^2/(2*9.8)

Vo = 44.3 = speed sin theta

sin theta = 44.3/50

theta = 62.4 deg up from horizontal

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