A 2.30 102 N force is pulling an 80.0 kg refrigerator across a horizontal surface. The force acts at an angle of 21.0° above the surface. The coefficient of kinetic friction is 0.200, and the refrigerator moves a distance of 7.00 m.
Find the work done by the kinetic frictional force.
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This question was asked and answered one or two days ago. Gowith BobPursley's answer, not mine. Try Googling it.
It did not work that's why I wanted to see if someone else had a better input. It was the wrong answer.
IT is right, Let me see how you implemented it.
Work done by friction= forcefriction*distance=mu(fn)*distance
where fnormal= mg-2.3E2Sin21
Fd= (.200)(.700X9.8X-2.3E2Xsin21)X(7)= Work done by friction=19790.15328.. that's what I got and it is wrong i believe
IT IS THE MONEKAY
To find the work done by the kinetic frictional force, we first need to calculate the frictional force acting on the refrigerator.
The frictional force can be determined using the formula:
frictional force = coefficient of friction * normal force
The normal force is equal to the weight of the refrigerator, which can be calculated using the formula:
normal force = mass * gravitational acceleration
Given that the mass of the refrigerator is 80.0 kg and the gravitational acceleration is approximately 9.81 m/s^2, we can calculate the normal force:
normal force = 80.0 kg * 9.81 m/s^2
Next, we can calculate the frictional force:
frictional force = 0.200 * normal force
Once we have determined the frictional force, we can then calculate the work done by the frictional force over a given distance by using the formula:
work = frictional force * distance * cosine(angle)
In this case, the distance is given as 7.00 m and the angle is 21.0°.
Substituting the values into the formula, we can calculate the work done by the kinetic frictional force.