posted by Marcus on .
A 67.0 kg base runner begins his slide into second base when moving at a speed of 3.5 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.
How much mechanical energy is lost due to friction acting on the runner?
How far does he slide?
(a) All of his (or her) initial kinetic energy is lost.
(b) Initial KE = (1/2) M V^2 = work done against friction = (M*g*Uk*X)
Uk = 0.7 is the coefficient of friction
Solve for X
X = V^2/(2*g*Uk)