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January 25, 2015

January 25, 2015

Posted by **traxx** on Sunday, November 14, 2010 at 8:21am.

// can someone tell me how to write that//

- Computer/assembly language -
**MathMate**, Sunday, November 14, 2010 at 3:08pm0x0024 is 2*16+4=36, which is what is required in RB 0x0036.

Basically, the hex value is converted into decimal, and each decimal digit is stored as a byte in RB.

The algorithm to do this is to divide the hex number by 10 (decimal), store the integer quotient in a register, and the remainder is the first byte in RB.

Repeat the process, i.e. divide the quotient by 10(dec.). However, the remainder must be shifted 8 bits to the left before adding to RB to get the next digit.

Repeat, if necessary, until the quotient is zero.

Example:

RA = 0x0024

RB = 0x0000

Divide by 0x000A to get

RA = 0x0003 (quotient)

RC = 0x0006 (remainder)

Add rb,rc

RB = 0x0006

if RA≠0, Repeat division

RA = 0x0000

RC = 0x0003 (remainder)

shift left 8 bits

RC = 0x0030

add rb,rc

RB = 0x0036

etc.

You will have to do some register management to put the quotient and remainder in the right places.

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