Posted by john on Sunday, November 14, 2010 at 3:21am.
Are you supposed to assume that the ice is intially 0 C? It could be lower.
The heat gained by the 11 g of ice, as it melts and rises to final temperature T, is equal to the heat lost by the 190 g of original liquid water, as it cools from 79 C to T.
Write that as an equation and solve for T. .
but i cant do it!!!
Change all the temp. to Kelvin first. Ice is 0C in solid form so there is a latent heat too.
4187(190/1000)(352-T)=333x1000x11/1000 + 4187(11/1000)(T-273)
Solve for T?
Then (T-273) is in Celsius.
Difference = 79 - (T-273)
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