Posted by Lee on Sunday, November 14, 2010 at 2:33am.
2e^7x +4=4
2e^7x=0
e^7x=0
ln1=0
so 7x=1
x=1/7
v.easy
Yes this would be very simple, except this is a logarithim equation. The answer you gave isn't correct either.
the e actually represect ln.
Lee, the solution that John gave you is correct according to the way you typed the question.
I have a feeling you meant to type
2e^(7x+4) = 4
if so, then
e^(7x+4) = 2
take ln of both sides
ln(e^(7x+4)) = ln2
(7x+4)lne = ln2 , but lne = 1
7x+4 = ln2
7x = ln2 - 4
x = (ln2 - 4)/7 or appr. - .4724
you are correct. I understand it now. You are such a fantastic help :)
Related Questions
pre-calculus - solve the exponential equation. express the solution in terms of ...
college - expects dividends paid to increase by 9.50 percent for the next two ...
Logs. - Can you please help me with the following log. problems? thanxs! Solve ...
Calc - I am having trouble with these two problems for my Calc class. I have ...
calculus - solve the exponential equation. Express the solution in terms of ...
Calculus - Consider the function below. f(x) = [1-(4/x)]^x (a) Use a graph to ...
college algebra - solve the following exponential equation. (e^x-e^-x)/2=6 what ...
math - Find equations for exponential functions that pass through the given pair...
math - round result to two decimal places...the answer i have is: 7.023 so two ...
probability - During the second round of the 1989 U.S. Open golf tournament, ...
For Further Reading
