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Posted by on Sunday, November 14, 2010 at 1:43am.

an automobile moving at a constant velocity of 50 ft/sec passes a gasoline station. 3 sec later, another automobile leaves the gasoline station and accelerates at the constant rate of 6.5 ft/sec2. how soon will the second automobile overtake the first?

  • physics - , Sunday, November 14, 2010 at 4:25am

    Let t be the time after the constant-velocity car passes the station.

    Require that they travel the same distance at time t
    50 t = (1/2)*(6.5)(t-3)^2

    Solve the resulting quadratic equation for t, which must exceed 3 s.

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