posted by Esora on .
A gun is accurately aimed at a dangerous criminal hanging from the gutter of a building. The target is well within the gun’s range, but the instant the gun is fired and the bullet moves with a speed v(sub0) , the criminal lets go and drops to the ground. What happens? The bullet:
1) hits the criminal regardless of the value v(sub0)
2) hits the criminal only if v(sub0) is large enough
3) misses the criminal.
If you were to draw the triangle, width would be 3m, the height would be 2m, and the hypotenuse would be 2^2+3^2=13?
I don't know how to prove that the bullet will hit the criminal with equations. please help! thank you!
the bullet accelerates down just as fast as the criminal accelerates down.
yes, but how would i prove that with equations?
Both are in the air for time t
How far does bullet drop from straight line in time t ?
The only vertical force on the bullet is m g
so it's height as a function of time is
h = (Vo sin T) t - (1/2) g t^2
but Vo sin T t is the straight line to the target ignoring gravity
so it drops (1/2) g t^2
so does the criminal
both of them move v=gt at the same rate.