Posted by **Esora** on Saturday, November 13, 2010 at 8:46pm.

A gun is accurately aimed at a dangerous criminal hanging from the gutter of a building. The target is well within the gun’s range, but the instant the gun is fired and the bullet moves with a speed v(sub0) , the criminal lets go and drops to the ground. What happens? The bullet:

1) hits the criminal regardless of the value v(sub0)

2) hits the criminal only if v(sub0) is large enough

3) misses the criminal.

If you were to draw the triangle, width would be 3m, the height would be 2m, and the hypotenuse would be 2^2+3^2=13?

I don't know how to prove that the bullet will hit the criminal with equations. please help! thank you!

- Physics -
**Damon**, Saturday, November 13, 2010 at 8:55pm
1)

the bullet accelerates down just as fast as the criminal accelerates down.

- Physics -
**Esora**, Saturday, November 13, 2010 at 8:57pm
yes, but how would i prove that with equations?

- Physics -
**Damon**, Saturday, November 13, 2010 at 9:09pm
Both are in the air for time t

How far does bullet drop from straight line in time t ?

The only vertical force on the bullet is m g

so it's height as a function of time is

h = (Vo sin T) t - (1/2) g t^2

but Vo sin T t is the straight line to the target ignoring gravity

so it drops (1/2) g t^2

so does the criminal

- Physics -
**bobpursley**, Saturday, November 13, 2010 at 9:10pm
both of them move v=gt at the same rate.

- Physics -
**Esora**, Saturday, November 13, 2010 at 9:11pm
thank you!

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