Posted by **Mike** on Saturday, November 13, 2010 at 8:36pm.

A square, 0.69 m on a side, is mounted so that it can rotate about an axis that passes through the center of the square. This axis is perpendicular to the plane of the square. A force of 17.1 N lies in this plane and is applied to the square. What is the magnitude of the maximum torque (in N*m) such that a force could produce?

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**Damon**, Saturday, November 13, 2010 at 8:58pm
force times maximum distance from axis which is half the diagonal of the square directed perpendicular to that diagonal.

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**Mike**, Saturday, November 13, 2010 at 9:01pm
So i multiply 0.69 by ?? 0.345?

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**Damon**, Saturday, November 13, 2010 at 9:14pm
diagonal is .69 * sqrt 2

half of that is (.69/2) *sqrt 2 = .488

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