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What is [OH-] of a solution containing 013 mol Ba(OH)2 and .021 mol KOH in .50L of H2O?

  • Chemistry -

    moles Ba(OH)2 = 0.013 (I don't see a decimal in the 013 number.)
    moles OH^- is twice that value.
    moles KOH = 0.21 and OH^- = same.
    Then total moles OH^-/total L = (OH^-)

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