Question

What is [OH-] of a solution containing 013 mol Ba(OH)2 and .021 mol KOH in .50L of H2O?

Answer 1

moles Ba(OH)2 = 0.013 (I don't see a decimal in the 013 number.)

moles OH^- is twice that value.
moles KOH = 0.21 and OH^- = same.
Then total moles OH^-/total L = (OH^-)