Posted by MaKenzie Smith on Saturday, November 13, 2010 at 7:16pm.
Solving systems of linear equations in three variables.
Ok so i don't really totally get these problems. Can you help me solve this one? and explain everything please?
- Algebra 2 - bobpursley, Saturday, November 13, 2010 at 7:28pm
put them in standard form (x,y,z)
You can solve these a number of ways, I will show you one.
add 1st and second equations
now multiply equation 2 by three, then add equations 2 and 3.
6x-5y=-4 check that.
now on these two remaining equations, multiply the first by 2, then subtract.
y=2 work back up to find x, then z.
- Algebra 2 - MaKenzie Smith, Saturday, November 13, 2010 at 7:39pm
Ok, this helps a lot, but hold on, i don't get how you got 7y=14? because when i multiply 3x+y=5 by (-2) i get -6x-2y=8. And then when combining that with 6x-5y=-4 i get -7y=4? how did you get 7y=14???
- Algebra 2 - bobpursley, Saturday, November 13, 2010 at 7:43pm
3x+y=5 multiply -2, your way
6x-5y=-4 to get
6x-5y=-4 add to get
- Algebra 2 - MaKenzie Smith, Saturday, November 13, 2010 at 7:46pm
Oh wait, i forgot to multiply the 5 by -2! (idk how i got 8, but watever its not that important) so right you would get y=2.
ok i think i get it now! THANKS!
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